Base | Representation |
---|---|
bin | 10101001000010101001… |
… | …011100111000011111001 |
3 | 12010211000011100210020021 |
4 | 111020111023213003321 |
5 | 142242301400424121 |
6 | 3031021535130441 |
7 | 206623154666116 |
oct | 25102513470371 |
9 | 5124004323207 |
10 | 1452054311161 |
11 | 50a8a3892763 |
12 | 1b5502073a21 |
13 | a6c0b15871c |
14 | 503cbad190d |
15 | 27b88044641 |
hex | 152152e70f9 |
1452054311161 has 2 divisors, whose sum is σ = 1452054311162. Its totient is φ = 1452054311160.
The previous prime is 1452054311111. The next prime is 1452054311171. The reversal of 1452054311161 is 1611134502541.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1427891163136 + 24163148025 = 1194944^2 + 155445^2 .
It is a cyclic number.
It is not a de Polignac number, because 1452054311161 - 215 = 1452054278393 is a prime.
It is a super-2 number, since 2×14520543111612 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1452054311101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726027155580 + 726027155581.
It is an arithmetic number, because the mean of its divisors is an integer number (726027155581).
Almost surely, 21452054311161 is an apocalyptic number.
It is an amenable number.
1452054311161 is a deficient number, since it is larger than the sum of its proper divisors (1).
1452054311161 is an equidigital number, since it uses as much as digits as its factorization.
1452054311161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 34.
The spelling of 1452054311161 in words is "one trillion, four hundred fifty-two billion, fifty-four million, three hundred eleven thousand, one hundred sixty-one".
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