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14521002556661 is a prime number
BaseRepresentation
bin1101001101001110111100…
…1100101111110011110101
31220102012020122011002102222
43103103233030233303311
53400403003123303121
650514505000012125
73026051660123516
oct323235714576365
956365218132388
1014521002556661
114699360421827
121766326461045
1381442b3a0433
14382b6ab8ca0d
151a2ad07d60ab
hexd34ef32fcf5

14521002556661 has 2 divisors, whose sum is σ = 14521002556662. Its totient is φ = 14521002556660.

The previous prime is 14521002556651. The next prime is 14521002556663. The reversal of 14521002556661 is 16665520012541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9148017635761 + 5372984920900 = 3024569^2 + 2317970^2 .

It is a cyclic number.

It is not a de Polignac number, because 14521002556661 - 26 = 14521002556597 is a prime.

Together with 14521002556663, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14521002556663) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7260501278330 + 7260501278331.

It is an arithmetic number, because the mean of its divisors is an integer number (7260501278331).

Almost surely, 214521002556661 is an apocalyptic number.

It is an amenable number.

14521002556661 is a deficient number, since it is larger than the sum of its proper divisors (1).

14521002556661 is an equidigital number, since it uses as much as digits as its factorization.

14521002556661 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432000, while the sum is 44.

The spelling of 14521002556661 in words is "fourteen trillion, five hundred twenty-one billion, two million, five hundred fifty-six thousand, six hundred sixty-one".