Base | Representation |
---|---|
bin | 11011000011000100… |
… | …11111000101001111 |
3 | 1101111000110002200212 |
4 | 31201202133011033 |
5 | 214214430111142 |
6 | 10400534313035 |
7 | 1022565200015 |
oct | 154142370517 |
9 | 41430402625 |
10 | 14521332047 |
11 | 6181a05772 |
12 | 29931b877b |
13 | 14a5622791 |
14 | 9ba8228b5 |
15 | 59ecb1d82 |
hex | 36189f14f |
14521332047 has 2 divisors, whose sum is σ = 14521332048. Its totient is φ = 14521332046.
The previous prime is 14521332031. The next prime is 14521332083. The reversal of 14521332047 is 74023312541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14521332047 - 24 = 14521332031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14521382047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7260666023 + 7260666024.
It is an arithmetic number, because the mean of its divisors is an integer number (7260666024).
Almost surely, 214521332047 is an apocalyptic number.
14521332047 is a deficient number, since it is larger than the sum of its proper divisors (1).
14521332047 is an equidigital number, since it uses as much as digits as its factorization.
14521332047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 32.
Adding to 14521332047 its reverse (74023312541), we get a palindrome (88544644588).
The spelling of 14521332047 in words is "fourteen billion, five hundred twenty-one million, three hundred thirty-two thousand, forty-seven".
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