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14524104022117 is a prime number
BaseRepresentation
bin1101001101011010100000…
…0011111001100001100101
31220102111020210002212012221
43103112220003321201211
53400430331112201432
650520140431112341
73026221560134044
oct323265003714145
956374223085187
1014524104022117
11469a702094718
121766a510726b1
13814803abc4b1
14382d82a4855b
151a2c12c1db97
hexd35a80f9865

14524104022117 has 2 divisors, whose sum is σ = 14524104022118. Its totient is φ = 14524104022116.

The previous prime is 14524104022111. The next prime is 14524104022201. The reversal of 14524104022117 is 71122040142541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13076801186596 + 1447302835521 = 3616186^2 + 1203039^2 .

It is a cyclic number.

It is not a de Polignac number, because 14524104022117 - 227 = 14523969804389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14524104022111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7262052011058 + 7262052011059.

It is an arithmetic number, because the mean of its divisors is an integer number (7262052011059).

Almost surely, 214524104022117 is an apocalyptic number.

It is an amenable number.

14524104022117 is a deficient number, since it is larger than the sum of its proper divisors (1).

14524104022117 is an equidigital number, since it uses as much as digits as its factorization.

14524104022117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17920, while the sum is 34.

Adding to 14524104022117 its reverse (71122040142541), we get a palindrome (85646144164658).

The spelling of 14524104022117 in words is "fourteen trillion, five hundred twenty-four billion, one hundred four million, twenty-two thousand, one hundred seventeen".