Base | Representation |
---|---|
bin | 10101001000101011001… |
… | …010011100101100011111 |
3 | 12010211221212022110200212 |
4 | 111020223022130230133 |
5 | 142244030303332221 |
6 | 3031122311443035 |
7 | 206635253460533 |
oct | 25105312345437 |
9 | 5124855273625 |
10 | 1452423105311 |
11 | 50aa72a84212 |
12 | 1b55a568647b |
13 | a6c69692209 |
14 | 50424a91bc3 |
15 | 27baa5e1b5b |
hex | 1522b29cb1f |
1452423105311 has 2 divisors, whose sum is σ = 1452423105312. Its totient is φ = 1452423105310.
The previous prime is 1452423105293. The next prime is 1452423105373. The reversal of 1452423105311 is 1135013242541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1452423105311 - 210 = 1452423104287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1452423105391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726211552655 + 726211552656.
It is an arithmetic number, because the mean of its divisors is an integer number (726211552656).
Almost surely, 21452423105311 is an apocalyptic number.
1452423105311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1452423105311 is an equidigital number, since it uses as much as digits as its factorization.
1452423105311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 1452423105311 its reverse (1135013242541), we get a palindrome (2587436347852).
The spelling of 1452423105311 in words is "one trillion, four hundred fifty-two billion, four hundred twenty-three million, one hundred five thousand, three hundred eleven".
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