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145252334421319 is a prime number
BaseRepresentation
bin100001000001101100110001…
…110010111100010101000111
3201001021222122221002102011111
4201001230301302330111013
5123014303240102440234
61232532000133545451
742411064153164106
oct4101546162742507
9631258587072144
10145252334421319
1142311195073274
121435aa60aa5287
13630830c39b228
1427c237151403d
1511bd52e947664
hex841b31cbc547

145252334421319 has 2 divisors, whose sum is σ = 145252334421320. Its totient is φ = 145252334421318.

The previous prime is 145252334421317. The next prime is 145252334421349. The reversal of 145252334421319 is 913124433252541.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 145252334421319 - 21 = 145252334421317 is a prime.

It is a super-2 number, since 2×1452523344213192 (a number of 29 digits) contains 22 as substring.

Together with 145252334421317, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145252334421317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72626167210659 + 72626167210660.

It is an arithmetic number, because the mean of its divisors is an integer number (72626167210660).

Almost surely, 2145252334421319 is an apocalyptic number.

145252334421319 is a deficient number, since it is larger than the sum of its proper divisors (1).

145252334421319 is an equidigital number, since it uses as much as digits as its factorization.

145252334421319 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3110400, while the sum is 49.

The spelling of 145252334421319 in words is "one hundred forty-five trillion, two hundred fifty-two billion, three hundred thirty-four million, four hundred twenty-one thousand, three hundred nineteen".