14530100111 has 2 divisors, whose sum is σ = 14530100112. Its totient is φ = 14530100110.

The previous prime is 14530100083. The next prime is 14530100113. The reversal of 14530100111 is 11100103541.

It is a strong prime.

It is an emirp because it is prime and its reverse (11100103541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14530100111 - 2⁶ = 14530100047 is a prime.

It is a super-2 number, since 2×14530100111² (a number of 21 digits) contains 22 as substring.

Together with 14530100113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14530100111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14530100113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7265050055 + 7265050056.

It is an arithmetic number, because the mean of its divisors is an integer number (7265050056).

Almost surely, 2^14530100111 is an apocalyptic number.

14530100111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14530100111 is an equidigital number, since it uses as much as digits as its factorization.

14530100111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 14530100111 its reverse (11100103541), we get a palindrome (25630203652).

The spelling of 14530100111 in words is "fourteen billion, five hundred thirty million, one hundred thousand, one hundred eleven".