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14534054053 is a prime number
BaseRepresentation
bin11011000100100110…
…00001000010100101
31101111220101110000021
431202103001002211
5214231204212203
610402111115141
71023111264301
oct154223010245
941456343007
1014534054053
116189104a22
122997512ab1
1314a81582ac
149bc3b4d01
155a0e765bd
hex3624c10a5

14534054053 has 2 divisors, whose sum is σ = 14534054054. Its totient is φ = 14534054052.

The previous prime is 14534054023. The next prime is 14534054089. The reversal of 14534054053 is 35045043541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11967922404 + 2566131649 = 109398^2 + 50657^2 .

It is a cyclic number.

It is not a de Polignac number, because 14534054053 - 213 = 14534045861 is a prime.

It is a super-2 number, since 2×145340540532 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14534054023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7267027026 + 7267027027.

It is an arithmetic number, because the mean of its divisors is an integer number (7267027027).

Almost surely, 214534054053 is an apocalyptic number.

It is an amenable number.

14534054053 is a deficient number, since it is larger than the sum of its proper divisors (1).

14534054053 is an equidigital number, since it uses as much as digits as its factorization.

14534054053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72000, while the sum is 34.

Adding to 14534054053 its reverse (35045043541), we get a palindrome (49579097594).

The spelling of 14534054053 in words is "fourteen billion, five hundred thirty-four million, fifty-four thousand, fifty-three".