1454000117 has 2 divisors, whose sum is σ = 1454000118. Its totient is φ = 1454000116.

The previous prime is 1454000113. The next prime is 1454000167. The reversal of 1454000117 is 7110004541.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1212850276 + 241149841 = 34826^2 + 15529^2 .

It is an emirp because it is prime and its reverse (7110004541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1454000117 - 2² = 1454000113 is a prime.

It is a super-2 number, since 2×1454000117² = 4228232680472027378, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1454000092 and 1454000101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1454000111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 727000058 + 727000059.

It is an arithmetic number, because the mean of its divisors is an integer number (727000059).

Almost surely, 2^1454000117 is an apocalyptic number.

It is an amenable number.

1454000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1454000117 is an equidigital number, since it uses as much as digits as its factorization.

1454000117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 560, while the sum is 23.

The square root of 1454000117 is about 38131.3534640458. The cubic root of 1454000117 is about 1132.8910534814.

Adding to 1454000117 its reverse (7110004541), we get a palindrome (8564004658).

The spelling of 1454000117 in words is "one billion, four hundred fifty-four million, one hundred seventeen", and thus it is an aban number.