Base | Representation |
---|---|
bin | 1000011101101010011… |
… | …0000010101001010111 |
3 | 111220022021020200022111 |
4 | 2013122212002221113 |
5 | 4340240214414132 |
6 | 150444011011451 |
7 | 13335115610626 |
oct | 2073246025127 |
9 | 456267220274 |
10 | 145401326167 |
11 | 56734292469 |
12 | 2421a739b87 |
13 | 10932907996 |
14 | 7074b1b6bd |
15 | 3baeeee647 |
hex | 21da982a57 |
145401326167 has 2 divisors, whose sum is σ = 145401326168. Its totient is φ = 145401326166.
The previous prime is 145401326159. The next prime is 145401326173. The reversal of 145401326167 is 761623104541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 145401326167 - 23 = 145401326159 is a prime.
It is a super-2 number, since 2×1454013261672 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145401326177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72700663083 + 72700663084.
It is an arithmetic number, because the mean of its divisors is an integer number (72700663084).
Almost surely, 2145401326167 is an apocalyptic number.
145401326167 is a deficient number, since it is larger than the sum of its proper divisors (1).
145401326167 is an equidigital number, since it uses as much as digits as its factorization.
145401326167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 40.
The spelling of 145401326167 in words is "one hundred forty-five billion, four hundred one million, three hundred twenty-six thousand, one hundred sixty-seven".
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