Base | Representation |
---|---|
bin | 11011000101010101… |
… | …00000011110100101 |
3 | 1101112022222022022022 |
4 | 31202222200132211 |
5 | 214234243242013 |
6 | 10402451112525 |
7 | 1023214523006 |
oct | 154252403645 |
9 | 41468868268 |
10 | 14540212133 |
11 | 6191630647 |
12 | 29995a2745 |
13 | 14a9503225 |
14 | 9bd1391ad |
15 | 5a1791008 |
hex | 362aa07a5 |
14540212133 has 2 divisors, whose sum is σ = 14540212134. Its totient is φ = 14540212132.
The previous prime is 14540212129. The next prime is 14540212139. The reversal of 14540212133 is 33121204541.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11487981124 + 3052231009 = 107182^2 + 55247^2 .
It is a cyclic number.
It is not a de Polignac number, because 14540212133 - 22 = 14540212129 is a prime.
It is a super-2 number, since 2×145402121332 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14540212139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270106066 + 7270106067.
It is an arithmetic number, because the mean of its divisors is an integer number (7270106067).
Almost surely, 214540212133 is an apocalyptic number.
It is an amenable number.
14540212133 is a deficient number, since it is larger than the sum of its proper divisors (1).
14540212133 is an equidigital number, since it uses as much as digits as its factorization.
14540212133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 14540212133 its reverse (33121204541), we get a palindrome (47661416674).
The spelling of 14540212133 in words is "fourteen billion, five hundred forty million, two hundred twelve thousand, one hundred thirty-three".
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