14540330533 has 2 divisors, whose sum is σ = 14540330534. Its totient is φ = 14540330532.

The previous prime is 14540330531. The next prime is 14540330549. The reversal of 14540330533 is 33503304541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11397270564 + 3143059969 = 106758^2 + 56063^2 .

It is a cyclic number.

It is not a de Polignac number, because 14540330533 - 2¹ = 14540330531 is a prime.

It is a super-2 number, since 2×14540330533² (a number of 21 digits) contains 22 as substring.

Together with 14540330531, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 14540330495 and 14540330504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14540330531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270165266 + 7270165267.

It is an arithmetic number, because the mean of its divisors is an integer number (7270165267).

Almost surely, 2^14540330533 is an apocalyptic number.

It is an amenable number.

14540330533 is a deficient number, since it is larger than the sum of its proper divisors (1).

14540330533 is an equidigital number, since it uses as much as digits as its factorization.

14540330533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400, while the sum is 31.

The spelling of 14540330533 in words is "fourteen billion, five hundred forty million, three hundred thirty thousand, five hundred thirty-three".