145427739341 has 2 divisors, whose sum is σ = 145427739342. Its totient is φ = 145427739340.

The previous prime is 145427739337. The next prime is 145427739343. The reversal of 145427739341 is 143937724541.

145427739341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108507654025 + 36920085316 = 329405^2 + 192146^2 .

It is a cyclic number.

It is not a de Polignac number, because 145427739341 - 2² = 145427739337 is a prime.

It is a super-2 number, since 2×145427739341² (a number of 23 digits) contains 22 as substring.

Together with 145427739343, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 145427739341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145427739343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72713869670 + 72713869671.

It is an arithmetic number, because the mean of its divisors is an integer number (72713869671).

Almost surely, 2^145427739341 is an apocalyptic number.

It is an amenable number.

145427739341 is a deficient number, since it is larger than the sum of its proper divisors (1).

145427739341 is an equidigital number, since it uses as much as digits as its factorization.

145427739341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2540160, while the sum is 50.

The spelling of 145427739341 in words is "one hundred forty-five billion, four hundred twenty-seven million, seven hundred thirty-nine thousand, three hundred forty-one".