145443941 has 2 divisors, whose sum is σ = 145443942. Its totient is φ = 145443940.

The previous prime is 145443913. The next prime is 145443943. The reversal of 145443941 is 149344541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114597025 + 30846916 = 10705^2 + 5554^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-145443941 is a prime.

It is a super-2 number, since 2×145443941² = 42307879947222962, which contains 22 as substring.

Together with 145443943, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145443943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72721970 + 72721971.

It is an arithmetic number, because the mean of its divisors is an integer number (72721971).

Almost surely, 2^145443941 is an apocalyptic number.

It is an amenable number.

145443941 is a deficient number, since it is larger than the sum of its proper divisors (1).

145443941 is an equidigital number, since it uses as much as digits as its factorization.

145443941 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34560, while the sum is 35.

The square root of 145443941 is about 12060.0141376368. The cubic root of 145443941 is about 525.8943980247.

The spelling of 145443941 in words is "one hundred forty-five million, four hundred forty-three thousand, nine hundred forty-one".