Base | Representation |
---|---|
bin | 1000011110001010010… |
… | …0010111010001110000 |
3 | 111220122120222022011012 |
4 | 2013202210113101300 |
5 | 4341023441312422 |
6 | 150505150210052 |
7 | 13341331655036 |
oct | 2074244272160 |
9 | 456576868135 |
10 | 145535104112 |
11 | 567a2854852 |
12 | 242574b3928 |
13 | 10954546c28 |
14 | 70887c2556 |
15 | 3bbbb274e2 |
hex | 21e2917470 |
145535104112 has 10 divisors (see below), whose sum is σ = 281974264248. Its totient is φ = 72767552048.
The previous prime is 145535104081. The next prime is 145535104151. The reversal of 145535104112 is 211401535541.
It is a super-3 number, since 3×1455351041123 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4547971988 + ... + 4547972019.
Almost surely, 2145535104112 is an apocalyptic number.
It is an amenable number.
145535104112 is a deficient number, since it is larger than the sum of its proper divisors (136439160136).
145535104112 is an equidigital number, since it uses as much as digits as its factorization.
145535104112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9095944015 (or 9095944009 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 145535104112 its reverse (211401535541), we get a palindrome (356936639653).
The spelling of 145535104112 in words is "one hundred forty-five billion, five hundred thirty-five million, one hundred four thousand, one hundred twelve".
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