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145536113117 is a prime number
BaseRepresentation
bin1000011110001010100…
…0001101100111011101
3111220122122212120020202
42013202220031213131
54341024221104432
6150505223553245
713341343356533
oct2074250154735
9456578776222
10145536113117
11567a338393a
12242578bb825
131095480b285
1470889a6153
153bbbc76462
hex21e2a0d9dd

145536113117 has 2 divisors, whose sum is σ = 145536113118. Its totient is φ = 145536113116.

The previous prime is 145536113101. The next prime is 145536113159. The reversal of 145536113117 is 711311635541.

145536113117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100152627961 + 45383485156 = 316469^2 + 213034^2 .

It is a cyclic number.

It is not a de Polignac number, because 145536113117 - 24 = 145536113101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145536110117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72768056558 + 72768056559.

It is an arithmetic number, because the mean of its divisors is an integer number (72768056559).

Almost surely, 2145536113117 is an apocalyptic number.

It is an amenable number.

145536113117 is a deficient number, since it is larger than the sum of its proper divisors (1).

145536113117 is an equidigital number, since it uses as much as digits as its factorization.

145536113117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 37800, while the sum is 38.

Adding to 145536113117 its reverse (711311635541), we get a palindrome (856847748658).

The spelling of 145536113117 in words is "one hundred forty-five billion, five hundred thirty-six million, one hundred thirteen thousand, one hundred seventeen".