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145543002433 is a prime number
BaseRepresentation
bin1000011110001100001…
…0011111100101000001
3111220200010211120121121
42013203002133211001
54341033002034213
6150510031352241
713341456052153
oct2074302374501
9456603746547
10145543002433
11567a7259994
122425a082681
1310956080caa
14708987aad3
153bbc68788d
hex21e309f941

145543002433 has 2 divisors, whose sum is σ = 145543002434. Its totient is φ = 145543002432.

The previous prime is 145543002389. The next prime is 145543002481. The reversal of 145543002433 is 334200345541.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129558963249 + 15984039184 = 359943^2 + 126428^2 .

It is a cyclic number.

It is not a de Polignac number, because 145543002433 - 225 = 145509448001 is a prime.

It is not a weakly prime, because it can be changed into another prime (145543002233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72771501216 + 72771501217.

It is an arithmetic number, because the mean of its divisors is an integer number (72771501217).

Almost surely, 2145543002433 is an apocalyptic number.

It is an amenable number.

145543002433 is a deficient number, since it is larger than the sum of its proper divisors (1).

145543002433 is an equidigital number, since it uses as much as digits as its factorization.

145543002433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 34.

Adding to 145543002433 its reverse (334200345541), we get a palindrome (479743347974).

The spelling of 145543002433 in words is "one hundred forty-five billion, five hundred forty-three million, two thousand, four hundred thirty-three".