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1457754209963 is a prime number
BaseRepresentation
bin10101001101101000111…
…010111111111010101011
312011100201101201122110022
4111031220322333322223
5142340440034204323
63033403311511055
7210214336223642
oct25155072777253
95140641648408
101457754209963
11512259280027
121b6632b2848b
13a7608cbc5cc
14507acb02359
1527dbd64d4c8
hex15368ebfeab

1457754209963 has 2 divisors, whose sum is σ = 1457754209964. Its totient is φ = 1457754209962.

The previous prime is 1457754209869. The next prime is 1457754210013. The reversal of 1457754209963 is 3699024577541.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (3699024577541) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1457754209963 is a prime.

It is a super-2 number, since 2×14577542099632 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1457754209896 and 1457754209905.

It is not a weakly prime, because it can be changed into another prime (1457754209563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 728877104981 + 728877104982.

It is an arithmetic number, because the mean of its divisors is an integer number (728877104982).

Almost surely, 21457754209963 is an apocalyptic number.

1457754209963 is a deficient number, since it is larger than the sum of its proper divisors (1).

1457754209963 is an equidigital number, since it uses as much as digits as its factorization.

1457754209963 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 57153600, while the sum is 62.

The spelling of 1457754209963 in words is "one trillion, four hundred fifty-seven billion, seven hundred fifty-four million, two hundred nine thousand, nine hundred sixty-three".