Base | Representation |
---|---|
bin | 10101001101101000111… |
… | …010111111111011011101 |
3 | 12011100201101201122112011 |
4 | 111031220322333323131 |
5 | 142340440034210023 |
6 | 3033403311511221 |
7 | 210214336224043 |
oct | 25155072777335 |
9 | 5140641648464 |
10 | 1457754210013 |
11 | 512259280072 |
12 | 1b6632b28511 |
13 | a7608cbc63a |
14 | 507acb02393 |
15 | 27dbd64d50d |
hex | 15368ebfedd |
1457754210013 has 2 divisors, whose sum is σ = 1457754210014. Its totient is φ = 1457754210012.
The previous prime is 1457754209963. The next prime is 1457754210079. The reversal of 1457754210013 is 3100124577541.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1378400446809 + 79353763204 = 1174053^2 + 281698^2 .
It is a cyclic number.
It is not a de Polignac number, because 1457754210013 - 225 = 1457720655581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1457754250013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 728877105006 + 728877105007.
It is an arithmetic number, because the mean of its divisors is an integer number (728877105007).
Almost surely, 21457754210013 is an apocalyptic number.
It is an amenable number.
1457754210013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1457754210013 is an equidigital number, since it uses as much as digits as its factorization.
1457754210013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 117600, while the sum is 40.
Adding to 1457754210013 its reverse (3100124577541), we get a palindrome (4557878787554).
The spelling of 1457754210013 in words is "one trillion, four hundred fifty-seven billion, seven hundred fifty-four million, two hundred ten thousand, thirteen".
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