Base | Representation |
---|---|
bin | 1000011111100011011… |
… | …0100001001101000101 |
3 | 111221121122110020220222 |
4 | 2013320312201031011 |
5 | 4342310143241432 |
6 | 151010223234125 |
7 | 13353521500052 |
oct | 2077066411505 |
9 | 457548406828 |
10 | 145908962117 |
11 | 56974894906 |
12 | 24340748945 |
13 | 109b3b34599 |
14 | 70c2300029 |
15 | 3bde875112 |
hex | 21f8da1345 |
145908962117 has 2 divisors, whose sum is σ = 145908962118. Its totient is φ = 145908962116.
The previous prime is 145908962107. The next prime is 145908962189. The reversal of 145908962117 is 711269809541.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 140959698916 + 4949263201 = 375446^2 + 70351^2 .
It is a cyclic number.
It is not a de Polignac number, because 145908962117 - 214 = 145908945733 is a prime.
It is a super-2 number, since 2×1459089621172 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145908962107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72954481058 + 72954481059.
It is an arithmetic number, because the mean of its divisors is an integer number (72954481059).
Almost surely, 2145908962117 is an apocalyptic number.
It is an amenable number.
145908962117 is a deficient number, since it is larger than the sum of its proper divisors (1).
145908962117 is an equidigital number, since it uses as much as digits as its factorization.
145908962117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1088640, while the sum is 53.
The spelling of 145908962117 in words is "one hundred forty-five billion, nine hundred eight million, nine hundred sixty-two thousand, one hundred seventeen".
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