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14593319453 is a prime number
BaseRepresentation
bin11011001011101010…
…00110001000011101
31101200000220102212002
431211311012020131
5214341342210303
610412025252045
71024431111566
oct154565061035
941600812762
1014593319453
116209603999
1229b3334025
1314b7508a8b
149c620116d
155a6281788
hex365d4621d

14593319453 has 2 divisors, whose sum is σ = 14593319454. Its totient is φ = 14593319452.

The previous prime is 14593319413. The next prime is 14593319483. The reversal of 14593319453 is 35491339541.

14593319453 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14593123204 + 196249 = 120802^2 + 443^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14593319453 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14593319398 and 14593319407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14593319413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7296659726 + 7296659727.

It is an arithmetic number, because the mean of its divisors is an integer number (7296659727).

Almost surely, 214593319453 is an apocalyptic number.

It is an amenable number.

14593319453 is a deficient number, since it is larger than the sum of its proper divisors (1).

14593319453 is an equidigital number, since it uses as much as digits as its factorization.

14593319453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 874800, while the sum is 47.

The spelling of 14593319453 in words is "fourteen billion, five hundred ninety-three million, three hundred nineteen thousand, four hundred fifty-three".