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14612556115039 is a prime number
BaseRepresentation
bin1101010010100100000000…
…1101110110110001011111
31220201221120011022202000111
43110221000031312301133
53403403003331140124
651024525434310451
73035502522413011
oct324510015666137
956657504282014
1014612556115039
114724171a84263
121780017588427
1381cc5c01790c
143873741321b1
151a518d23b494
hexd4a40376c5f

14612556115039 has 2 divisors, whose sum is σ = 14612556115040. Its totient is φ = 14612556115038.

The previous prime is 14612556115037. The next prime is 14612556115061. The reversal of 14612556115039 is 93051165521641.

14612556115039 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14612556115039 - 21 = 14612556115037 is a prime.

Together with 14612556115037, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 14612556114983 and 14612556115001.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14612556115037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7306278057519 + 7306278057520.

It is an arithmetic number, because the mean of its divisors is an integer number (7306278057520).

Almost surely, 214612556115039 is an apocalyptic number.

14612556115039 is a deficient number, since it is larger than the sum of its proper divisors (1).

14612556115039 is an equidigital number, since it uses as much as digits as its factorization.

14612556115039 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972000, while the sum is 49.

The spelling of 14612556115039 in words is "fourteen trillion, six hundred twelve billion, five hundred fifty-six million, one hundred fifteen thousand, thirty-nine".