Base | Representation |
---|---|
bin | 11011001111001101… |
… | …11100001100000111 |
3 | 1101202010001122200221 |
4 | 31213212330030013 |
5 | 214422012210033 |
6 | 10415013045211 |
7 | 1025242556461 |
oct | 154746741407 |
9 | 41663048627 |
10 | 14623163143 |
11 | 62244379a6 |
12 | 2a01326807 |
13 | 14c0757874 |
14 | 9ca16d131 |
15 | 5a8bc912d |
hex | 3679bc307 |
14623163143 has 2 divisors, whose sum is σ = 14623163144. Its totient is φ = 14623163142.
The previous prime is 14623163101. The next prime is 14623163161. The reversal of 14623163143 is 34136132641.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14623163143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14623163099 and 14623163108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14623163183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7311581571 + 7311581572.
It is an arithmetic number, because the mean of its divisors is an integer number (7311581572).
Almost surely, 214623163143 is an apocalyptic number.
14623163143 is a deficient number, since it is larger than the sum of its proper divisors (1).
14623163143 is an equidigital number, since it uses as much as digits as its factorization.
14623163143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 31104, while the sum is 34.
Adding to 14623163143 its reverse (34136132641), we get a palindrome (48759295784).
The spelling of 14623163143 in words is "fourteen billion, six hundred twenty-three million, one hundred sixty-three thousand, one hundred forty-three".
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