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1463507212031 is a prime number
BaseRepresentation
bin10101010010111111110…
…100111101011011111111
312011220120100000102122222
4111102333310331123333
5142434230321241111
63040154222355555
7210510034022504
oct25227764753377
95156510012588
101463507212031
11514740738697
121b777972bbbb
13a8014b57247
1450b96bb74ab
15281087467db
hex154bfd3d6ff

1463507212031 has 2 divisors, whose sum is σ = 1463507212032. Its totient is φ = 1463507212030.

The previous prime is 1463507212021. The next prime is 1463507212033. The reversal of 1463507212031 is 1302127053641.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1463507212031 - 26 = 1463507211967 is a prime.

It is a super-2 number, since 2×14635072120312 (a number of 25 digits) contains 22 as substring.

Together with 1463507212033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1463507211982 and 1463507212000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1463507212033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 731753606015 + 731753606016.

It is an arithmetic number, because the mean of its divisors is an integer number (731753606016).

Almost surely, 21463507212031 is an apocalyptic number.

1463507212031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1463507212031 is an equidigital number, since it uses as much as digits as its factorization.

1463507212031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30240, while the sum is 35.

The spelling of 1463507212031 in words is "one trillion, four hundred sixty-three billion, five hundred seven million, two hundred twelve thousand, thirty-one".