Base | Representation |
---|---|
bin | 1101011000100101101100… |
… | …0101100001110100110001 |
3 | 1221002211210100022112012202 |
4 | 3112021123011201310301 |
5 | 3412102021022211032 |
6 | 51144250542032545 |
7 | 3046126222140134 |
oct | 326113305416461 |
9 | 57084710275182 |
10 | 14716086132017 |
11 | 4764069a79366 |
12 | 17980ab578755 |
13 | 82994ac735aa |
14 | 38c395d2621b |
15 | 1a7bec311d62 |
hex | d625b161d31 |
14716086132017 has 2 divisors, whose sum is σ = 14716086132018. Its totient is φ = 14716086132016.
The previous prime is 14716086131963. The next prime is 14716086132019. The reversal of 14716086132017 is 71023168061741.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12942610637056 + 1773475494961 = 3597584^2 + 1331719^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14716086132017 is a prime.
Together with 14716086132019, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14716086132019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7358043066008 + 7358043066009.
It is an arithmetic number, because the mean of its divisors is an integer number (7358043066009).
Almost surely, 214716086132017 is an apocalyptic number.
It is an amenable number.
14716086132017 is a deficient number, since it is larger than the sum of its proper divisors (1).
14716086132017 is an equidigital number, since it uses as much as digits as its factorization.
14716086132017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 338688, while the sum is 47.
The spelling of 14716086132017 in words is "fourteen trillion, seven hundred sixteen billion, eighty-six million, one hundred thirty-two thousand, seventeen".
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