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1473041131 is a prime number
BaseRepresentation
bin101011111001100…
…1101001011101011
310210122210020112221
41113303031023223
511004044304011
6402100214511
751334433362
oct12763151353
93718706487
101473041131
11696547671
1235139a437
131a6243593
14dd8c67d9
15894c1971
hex57ccd2eb

1473041131 has 2 divisors, whose sum is σ = 1473041132. Its totient is φ = 1473041130.

The previous prime is 1473041117. The next prime is 1473041149. The reversal of 1473041131 is 1311403741.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (1311403741) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1473041131 - 25 = 1473041099 is a prime.

It is a super-2 number, since 2×14730411312 = 4339700347235518322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1473041096 and 1473041105.

It is not a weakly prime, because it can be changed into another prime (1473041161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 736520565 + 736520566.

It is an arithmetic number, because the mean of its divisors is an integer number (736520566).

Almost surely, 21473041131 is an apocalyptic number.

1473041131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1473041131 is an equidigital number, since it uses as much as digits as its factorization.

1473041131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

The square root of 1473041131 is about 38380.2179644671. The cubic root of 1473041131 is about 1137.8149205900.

Adding to 1473041131 its reverse (1311403741), we get a palindrome (2784444872).

The spelling of 1473041131 in words is "one billion, four hundred seventy-three million, forty-one thousand, one hundred thirty-one".