147521143000471 has 2 divisors, whose sum is σ = 147521143000472. Its totient is φ = 147521143000470.

The previous prime is 147521143000453. The next prime is 147521143000501. The reversal of 147521143000471 is 174000341125741.

It is a happy number.

147521143000471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 147521143000471 - 2³⁹ = 146971387186583 is a prime.

It is a super-3 number, since 3×147521143000471³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (147521143000271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73760571500235 + 73760571500236.

It is an arithmetic number, because the mean of its divisors is an integer number (73760571500236).

Almost surely, 2^{147521143000471} is an apocalyptic number.

147521143000471 is a deficient number, since it is larger than the sum of its proper divisors (1).

147521143000471 is an equidigital number, since it uses as much as digits as its factorization.

147521143000471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 94080, while the sum is 40.

The spelling of 147521143000471 in words is "one hundred forty-seven trillion, five hundred twenty-one billion, one hundred forty-three million, four hundred seventy-one", and thus it is an aban number.