Base | Representation |
---|---|
bin | 10101011110111011110… |
… | …000011010001100000001 |
3 | 12020010122112201011201022 |
4 | 111132323300122030001 |
5 | 143142002343441342 |
6 | 3050114102515225 |
7 | 211442452231451 |
oct | 25367360321401 |
9 | 5203575634638 |
10 | 1476323812097 |
11 | 51a118338a52 |
12 | 1ba155a35b15 |
13 | a92a8234674 |
14 | 51651041d61 |
15 | 28608a1c9d2 |
hex | 157bbc1a301 |
1476323812097 has 2 divisors, whose sum is σ = 1476323812098. Its totient is φ = 1476323812096.
The previous prime is 1476323812081. The next prime is 1476323812099. The reversal of 1476323812097 is 7902183236741.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 900608592016 + 575715220081 = 949004^2 + 758759^2 .
It is a cyclic number.
It is not a de Polignac number, because 1476323812097 - 24 = 1476323812081 is a prime.
Together with 1476323812099, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1476323812099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 738161906048 + 738161906049.
It is an arithmetic number, because the mean of its divisors is an integer number (738161906049).
Almost surely, 21476323812097 is an apocalyptic number.
It is an amenable number.
1476323812097 is a deficient number, since it is larger than the sum of its proper divisors (1).
1476323812097 is an equidigital number, since it uses as much as digits as its factorization.
1476323812097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3048192, while the sum is 53.
The spelling of 1476323812097 in words is "one trillion, four hundred seventy-six billion, three hundred twenty-three million, eight hundred twelve thousand, ninety-seven".
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