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147685022401393 is a prime number
BaseRepresentation
bin100001100101000110011001…
…010011001000001101110001
3201100220112212010201001222001
4201211012121103020031301
5123324132411213321033
61242033321312014001
743051614346633501
oct4145063123101561
9640815763631861
10147685022401393
1143069959006714
121469241b231301
13645383a4a1379
142867dc9595a01
15121195de05e7d
hex8651994c8371

147685022401393 has 2 divisors, whose sum is σ = 147685022401394. Its totient is φ = 147685022401392.

The previous prime is 147685022401391. The next prime is 147685022401429. The reversal of 147685022401393 is 393104220586741.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130921377799744 + 16763644601649 = 11442088^2 + 4094343^2 .

It is a cyclic number.

It is not a de Polignac number, because 147685022401393 - 21 = 147685022401391 is a prime.

Together with 147685022401391, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (147685022401391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73842511200696 + 73842511200697.

It is an arithmetic number, because the mean of its divisors is an integer number (73842511200697).

It is a 1-persistent number, because it is pandigital, but 2⋅147685022401393 = 295370044802786 is not.

Almost surely, 2147685022401393 is an apocalyptic number.

It is an amenable number.

147685022401393 is a deficient number, since it is larger than the sum of its proper divisors (1).

147685022401393 is an equidigital number, since it uses as much as digits as its factorization.

147685022401393 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8709120, while the sum is 55.

The spelling of 147685022401393 in words is "one hundred forty-seven trillion, six hundred eighty-five billion, twenty-two million, four hundred one thousand, three hundred ninety-three".