147685022401391 has 2 divisors, whose sum is σ = 147685022401392. Its totient is φ = 147685022401390.

The previous prime is 147685022401331. The next prime is 147685022401393. The reversal of 147685022401391 is 193104220586741.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 147685022401391 - 2⁶ = 147685022401327 is a prime.

It is a super-3 number, since 3×147685022401391³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 147685022401393, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (147685022401393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73842511200695 + 73842511200696.

It is an arithmetic number, because the mean of its divisors is an integer number (73842511200696).

It is a 1-persistent number, because it is pandigital, but 2⋅147685022401391 = 295370044802782 is not.

Almost surely, 2^{147685022401391} is an apocalyptic number.

147685022401391 is a deficient number, since it is larger than the sum of its proper divisors (1).

147685022401391 is an equidigital number, since it uses as much as digits as its factorization.

147685022401391 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2903040, while the sum is 53.

The spelling of 147685022401391 in words is "one hundred forty-seven trillion, six hundred eighty-five billion, twenty-two million, four hundred one thousand, three hundred ninety-one".