Base | Representation |
---|---|
bin | 1101011011101001110000… |
… | …1101000101100100001011 |
3 | 1221021212122100220122012212 |
4 | 3112322130031011210023 |
5 | 3413432313332140021 |
6 | 51224353330455335 |
7 | 3053001414522131 |
oct | 326723415054413 |
9 | 57255570818185 |
10 | 14768718240011 |
11 | 478441847707a |
12 | 17a6339a3454b |
13 | 8318b8118868 |
14 | 390b4a055751 |
15 | 1a927ccca85b |
hex | d6e9c34590b |
14768718240011 has 2 divisors, whose sum is σ = 14768718240012. Its totient is φ = 14768718240010.
The previous prime is 14768718239923. The next prime is 14768718240013. The reversal of 14768718240011 is 11004281786741.
It is a happy number.
14768718240011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14768718240011 - 226 = 14768651131147 is a prime.
Together with 14768718240013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14768718240013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7384359120005 + 7384359120006.
It is an arithmetic number, because the mean of its divisors is an integer number (7384359120006).
Almost surely, 214768718240011 is an apocalyptic number.
14768718240011 is a deficient number, since it is larger than the sum of its proper divisors (1).
14768718240011 is an equidigital number, since it uses as much as digits as its factorization.
14768718240011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 602112, while the sum is 50.
The spelling of 14768718240011 in words is "fourteen trillion, seven hundred sixty-eight billion, seven hundred eighteen million, two hundred forty thousand, eleven".
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