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14771440133 is a prime number
BaseRepresentation
bin11011100000111001…
…00100101000000101
31102010110001220111022
431300130210220011
5220222442041013
610441431120525
71032023112062
oct156034445005
942113056438
1014771440133
1162a010266a
122a42b13145
1315153a2428
14a01b29c69
155b6c18008
hex370724a05

14771440133 has 2 divisors, whose sum is σ = 14771440134. Its totient is φ = 14771440132.

The previous prime is 14771440129. The next prime is 14771440193. The reversal of 14771440133 is 33104417741.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11646294724 + 3125145409 = 107918^2 + 55903^2 .

It is a cyclic number.

It is not a de Polignac number, because 14771440133 - 22 = 14771440129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14771440093 and 14771440102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14771440193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7385720066 + 7385720067.

It is an arithmetic number, because the mean of its divisors is an integer number (7385720067).

Almost surely, 214771440133 is an apocalyptic number.

It is an amenable number.

14771440133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14771440133 is an equidigital number, since it uses as much as digits as its factorization.

14771440133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28224, while the sum is 35.

Adding to 14771440133 its reverse (33104417741), we get a palindrome (47875857874).

The spelling of 14771440133 in words is "fourteen billion, seven hundred seventy-one million, four hundred forty thousand, one hundred thirty-three".