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14819429318401 is a prime number
BaseRepresentation
bin1101011110100110101011…
…0100011111111100000001
31221110201112111202100000101
43113221222310133330001
53420300142401142101
651303541333122401
73056445162546541
oct327515264377401
957421474670011
1014819429318401
1147a3980565914
1217b4130a89401
1383660a2a6316
1439339ada5321
151aa749cd0401
hexd7a6ad1ff01

14819429318401 has 2 divisors, whose sum is σ = 14819429318402. Its totient is φ = 14819429318400.

The previous prime is 14819429318399. The next prime is 14819429318467. The reversal of 14819429318401 is 10481392491841.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13690999018225 + 1128430300176 = 3700135^2 + 1062276^2 .

It is an emirp because it is prime and its reverse (10481392491841) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14819429318401 - 21 = 14819429318399 is a prime.

Together with 14819429318399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14819429318471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7409714659200 + 7409714659201.

It is an arithmetic number, because the mean of its divisors is an integer number (7409714659201).

Almost surely, 214819429318401 is an apocalyptic number.

It is an amenable number.

14819429318401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14819429318401 is an equidigital number, since it uses as much as digits as its factorization.

14819429318401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1990656, while the sum is 55.

The spelling of 14819429318401 in words is "fourteen trillion, eight hundred nineteen billion, four hundred twenty-nine million, three hundred eighteen thousand, four hundred one".