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14825701151 is a prime number
BaseRepresentation
bin11011100111010111…
…00011111100011111
31102021020011122121122
431303223203330133
5220330334414101
610451050121155
71033252244342
oct156353437437
942236148548
1014825701151
1163187a3788
122a591201bb
1315236c0141
14a09012459
155bb88551b
hex373ae3f1f

14825701151 has 2 divisors, whose sum is σ = 14825701152. Its totient is φ = 14825701150.

The previous prime is 14825701129. The next prime is 14825701153. The reversal of 14825701151 is 15110752841.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14825701151 - 26 = 14825701087 is a prime.

Together with 14825701153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14825701153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7412850575 + 7412850576.

It is an arithmetic number, because the mean of its divisors is an integer number (7412850576).

Almost surely, 214825701151 is an apocalyptic number.

14825701151 is a deficient number, since it is larger than the sum of its proper divisors (1).

14825701151 is an equidigital number, since it uses as much as digits as its factorization.

14825701151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11200, while the sum is 35.

The spelling of 14825701151 in words is "fourteen billion, eight hundred twenty-five million, seven hundred one thousand, one hundred fifty-one".