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14872592250053 is a prime number
BaseRepresentation
bin1101100001101100101110…
…0100111111010011000101
31221122210202112012002011222
43120123023210333103011
53422133032104000203
651344212523210125
73063336462164426
oct330331344772305
957583675162158
1014872592250053
11481448166326a
1218024a9076945
1383b630406525
14395ba17d164d
151abd0c1a0038
hexd86cb93f4c5

14872592250053 has 2 divisors, whose sum is σ = 14872592250054. Its totient is φ = 14872592250052.

The previous prime is 14872592249987. The next prime is 14872592250091. The reversal of 14872592250053 is 35005229527841.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14158528379524 + 714063870529 = 3762782^2 + 845023^2 .

It is a cyclic number.

It is not a de Polignac number, because 14872592250053 - 212 = 14872592245957 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14872592249977 and 14872592250004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14872592250653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7436296125026 + 7436296125027.

It is an arithmetic number, because the mean of its divisors is an integer number (7436296125027).

Almost surely, 214872592250053 is an apocalyptic number.

It is an amenable number.

14872592250053 is a deficient number, since it is larger than the sum of its proper divisors (1).

14872592250053 is an equidigital number, since it uses as much as digits as its factorization.

14872592250053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048000, while the sum is 53.

Subtracting from 14872592250053 its sum of digits (53), we obtain a square (14872592250000 = 38565002).

The spelling of 14872592250053 in words is "fourteen trillion, eight hundred seventy-two billion, five hundred ninety-two million, two hundred fifty thousand, fifty-three".