Base | Representation |
---|---|
bin | 11011110000101010… |
… | …00001110111010111 |
3 | 1102110122220102010121 |
4 | 31320111001313113 |
5 | 221010320233341 |
6 | 10502513332411 |
7 | 1035220123321 |
oct | 157025016727 |
9 | 42418812117 |
10 | 14903680471 |
11 | 63588147a9 |
12 | 2a7b267107 |
13 | 15368c3854 |
14 | a15510611 |
15 | 5c363a4d1 |
hex | 378541dd7 |
14903680471 has 2 divisors, whose sum is σ = 14903680472. Its totient is φ = 14903680470.
The previous prime is 14903680469. The next prime is 14903680487. The reversal of 14903680471 is 17408630941.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14903680471 - 21 = 14903680469 is a prime.
It is a super-3 number, since 3×149036804713 (a number of 31 digits) contains 333 as substring.
Together with 14903680469, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14903680171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7451840235 + 7451840236.
It is an arithmetic number, because the mean of its divisors is an integer number (7451840236).
Almost surely, 214903680471 is an apocalyptic number.
14903680471 is a deficient number, since it is larger than the sum of its proper divisors (1).
14903680471 is an equidigital number, since it uses as much as digits as its factorization.
14903680471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 43.
The spelling of 14903680471 in words is "fourteen billion, nine hundred three million, six hundred eighty thousand, four hundred seventy-one".
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