14910433 has 2 divisors, whose sum is σ = 14910434. Its totient is φ = 14910432.

The previous prime is 14910407. The next prime is 14910439. The reversal of 14910433 is 33401941.

It is a happy number.

14910433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9560464 + 5349969 = 3092^2 + 2313^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14910433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14910398 and 14910407.

It is not a weakly prime, because it can be changed into another prime (14910439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7455216 + 7455217.

It is an arithmetic number, because the mean of its divisors is an integer number (7455217).

Almost surely, 2^14910433 is an apocalyptic number.

It is an amenable number.

14910433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14910433 is an equidigital number, since it uses as much as digits as its factorization.

14910433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

The square root of 14910433 is about 3861.4029833728. The cubic root of 14910433 is about 246.1293577927.

The spelling of 14910433 in words is "fourteen million, nine hundred ten thousand, four hundred thirty-three".