Base | Representation |
---|---|
bin | 100001111001111000101000… |
… | …010001010100001010100011 |
3 | 201112222002121202110122202021 |
4 | 201321320220101110022203 |
5 | 124021033120123211321 |
6 | 1245045421042002311 |
7 | 43260040552661452 |
oct | 4171705021241243 |
9 | 645862552418667 |
10 | 149113350210211 |
11 | 4356a6868a8a52 |
12 | 148831bb346397 |
13 | 6528436bac59a |
14 | 28b71a60c2b99 |
15 | 1238ba8e80941 |
hex | 879e284542a3 |
149113350210211 has 2 divisors, whose sum is σ = 149113350210212. Its totient is φ = 149113350210210.
The previous prime is 149113350210197. The next prime is 149113350210229. The reversal of 149113350210211 is 112012053311941.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-149113350210211 is a prime.
It is not a weakly prime, because it can be changed into another prime (149113350216211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74556675105105 + 74556675105106.
It is an arithmetic number, because the mean of its divisors is an integer number (74556675105106).
Almost surely, 2149113350210211 is an apocalyptic number.
149113350210211 is a deficient number, since it is larger than the sum of its proper divisors (1).
149113350210211 is an equidigital number, since it uses as much as digits as its factorization.
149113350210211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 34.
The spelling of 149113350210211 in words is "one hundred forty-nine trillion, one hundred thirteen billion, three hundred fifty million, two hundred ten thousand, two hundred eleven".
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