Base | Representation |
---|---|
bin | 1000101011111110100… |
… | …0100000000010100111 |
3 | 112021020001211100210122 |
4 | 2022333220200002213 |
5 | 4421122423001234 |
6 | 152321155512155 |
7 | 13532255446346 |
oct | 2127750400247 |
9 | 467201740718 |
10 | 149243953319 |
11 | 5832635908a |
12 | 24b115b865b |
13 | 110c5a48666 |
14 | 731b1c7b5d |
15 | 3d3753a92e |
hex | 22bfa200a7 |
149243953319 has 2 divisors, whose sum is σ = 149243953320. Its totient is φ = 149243953318.
The previous prime is 149243953301. The next prime is 149243953333. The reversal of 149243953319 is 913359342941.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 149243953319 - 220 = 149242904743 is a prime.
It is a super-2 number, since 2×1492439533192 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (149243953349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74621976659 + 74621976660.
It is an arithmetic number, because the mean of its divisors is an integer number (74621976660).
Almost surely, 2149243953319 is an apocalyptic number.
149243953319 is a deficient number, since it is larger than the sum of its proper divisors (1).
149243953319 is an equidigital number, since it uses as much as digits as its factorization.
149243953319 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3149280, while the sum is 53.
The spelling of 149243953319 in words is "one hundred forty-nine billion, two hundred forty-three million, nine hundred fifty-three thousand, three hundred nineteen".
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