Base | Representation |
---|---|
bin | 11011110011010001… |
… | …11101001001110110 |
3 | 1102112012022011120000 |
4 | 31321220331021312 |
5 | 221031433300040 |
6 | 10505021052130 |
7 | 1035605124513 |
oct | 157150751166 |
9 | 42465264500 |
10 | 14925681270 |
11 | 636a181285 |
12 | 2a866b7046 |
13 | 153b327886 |
14 | a183da30a |
15 | 5c5534130 |
hex | 379a3d276 |
14925681270 has 40 divisors (see below), whose sum is σ = 40133500704. Its totient is φ = 3980181456.
The previous prime is 14925681217. The next prime is 14925681271. The reversal of 14925681270 is 7218652941.
14925681270 is a `hidden beast` number, since 1 + 4 + 9 + 2 + 568 + 12 + 70 = 666.
It is a super-2 number, since 2×149256812702 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14925681271) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 9212574 + ... + 9214193.
Almost surely, 214925681270 is an apocalyptic number.
14925681270 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14925681270 is an abundant number, since it is smaller than the sum of its proper divisors (25207819434).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14925681270 is a wasteful number, since it uses less digits than its factorization.
14925681270 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18426786 (or 18426777 counting only the distinct ones).
The product of its (nonzero) digits is 241920, while the sum is 45.
The spelling of 14925681270 in words is "fourteen billion, nine hundred twenty-five million, six hundred eighty-one thousand, two hundred seventy".
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