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149384113 is a prime number
BaseRepresentation
bin10001110011101…
…10101110110001
3101102002111110221
420321312232301
5301220242423
622453453041
73462513124
oct1071665661
9342074427
10149384113
117736154a
1242041181
1324c44788
1415ba83bb
15d1abe5d
hex8e76bb1

149384113 has 2 divisors, whose sum is σ = 149384114. Its totient is φ = 149384112.

The previous prime is 149384111. The next prime is 149384119. The reversal of 149384113 is 311483941.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125059489 + 24324624 = 11183^2 + 4932^2 .

It is a cyclic number.

It is not a de Polignac number, because 149384113 - 21 = 149384111 is a prime.

It is a super-2 number, since 2×1493841132 = 44631226433593538, which contains 22 as substring.

Together with 149384111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (149384111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74692056 + 74692057.

It is an arithmetic number, because the mean of its divisors is an integer number (74692057).

Almost surely, 2149384113 is an apocalyptic number.

It is an amenable number.

149384113 is a deficient number, since it is larger than the sum of its proper divisors (1).

149384113 is an equidigital number, since it uses as much as digits as its factorization.

149384113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10368, while the sum is 34.

The square root of 149384113 is about 12222.2793700684. The cubic root of 149384113 is about 530.6010897137.

The spelling of 149384113 in words is "one hundred forty-nine million, three hundred eighty-four thousand, one hundred thirteen".