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149786917681439 is a prime number
BaseRepresentation
bin100010000011101011111100…
…000001010011100100011111
3201122100111012211111110122002
4202003223330001103210133
5124113102101411301224
61250323054322312515
743356514312011053
oct4203537401234437
9648314184443562
10149786917681439
11437aa303104545
121497185b7b873b
136576acc0b554c
1428dba22aa1c63
15124b47c6e79ae
hex883afc05391f

149786917681439 has 2 divisors, whose sum is σ = 149786917681440. Its totient is φ = 149786917681438.

The previous prime is 149786917681433. The next prime is 149786917681441. The reversal of 149786917681439 is 934186719687941.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 149786917681439 - 212 = 149786917677343 is a prime.

It is a super-2 number, since 2×1497869176814392 (a number of 29 digits) contains 22 as substring.

Together with 149786917681441, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (149786917681433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74893458840719 + 74893458840720.

It is an arithmetic number, because the mean of its divisors is an integer number (74893458840720).

Almost surely, 2149786917681439 is an apocalyptic number.

149786917681439 is a deficient number, since it is larger than the sum of its proper divisors (1).

149786917681439 is an equidigital number, since it uses as much as digits as its factorization.

149786917681439 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3950456832, while the sum is 83.

The spelling of 149786917681439 in words is "one hundred forty-nine trillion, seven hundred eighty-six billion, nine hundred seventeen million, six hundred eighty-one thousand, four hundred thirty-nine".