Base | Representation |
---|---|
bin | 1000101110110100000… |
… | …0001001000011011011 |
3 | 112100012010002220111221 |
4 | 2023231000021003123 |
5 | 4424202303002324 |
6 | 152524510232511 |
7 | 13560160345636 |
oct | 2135500110333 |
9 | 470163086457 |
10 | 150005125339 |
11 | 58686a89973 |
12 | 250a44b5737 |
13 | 111b76552c4 |
14 | 7390326c1d |
15 | 3d7e2930e4 |
hex | 22ed0090db |
150005125339 has 2 divisors, whose sum is σ = 150005125340. Its totient is φ = 150005125338.
The previous prime is 150005125273. The next prime is 150005125373. The reversal of 150005125339 is 933521500051.
It is an a-pointer prime, because the next prime (150005125373) can be obtained adding 150005125339 to its sum of digits (34).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 150005125339 - 213 = 150005117147 is a prime.
It is not a weakly prime, because it can be changed into another prime (150005125139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75002562669 + 75002562670.
It is an arithmetic number, because the mean of its divisors is an integer number (75002562670).
Almost surely, 2150005125339 is an apocalyptic number.
150005125339 is a deficient number, since it is larger than the sum of its proper divisors (1).
150005125339 is an equidigital number, since it uses as much as digits as its factorization.
150005125339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20250, while the sum is 34.
The spelling of 150005125339 in words is "one hundred fifty billion, five million, one hundred twenty-five thousand, three hundred thirty-nine".
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