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150014205511 is a prime number
BaseRepresentation
bin1000101110110110001…
…0110001111001000111
3112100012202012020011121
42023231202301321013
54424212114034021
6152525433014411
713560330464512
oct2135542617107
9470182166147
10150014205511
1158691120a45
12250a7554407
13111b94b42a1
14739160bd79
153d7ee88741
hex22ed8b1e47

150014205511 has 2 divisors, whose sum is σ = 150014205512. Its totient is φ = 150014205510.

The previous prime is 150014205499. The next prime is 150014205563. The reversal of 150014205511 is 115502410051.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 150014205511 - 211 = 150014203463 is a prime.

It is a super-2 number, since 2×1500142055112 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150014205311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75007102755 + 75007102756.

It is an arithmetic number, because the mean of its divisors is an integer number (75007102756).

Almost surely, 2150014205511 is an apocalyptic number.

150014205511 is a deficient number, since it is larger than the sum of its proper divisors (1).

150014205511 is an equidigital number, since it uses as much as digits as its factorization.

150014205511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1000, while the sum is 25.

Adding to 150014205511 its reverse (115502410051), we get a palindrome (265516615562).

The spelling of 150014205511 in words is "one hundred fifty billion, fourteen million, two hundred five thousand, five hundred eleven".