Base | Representation |
---|---|
bin | 1000101110111010100… |
… | …0100111100100000111 |
3 | 112100021000122100201101 |
4 | 2023232220213210013 |
5 | 4424231310411122 |
6 | 152531325240531 |
7 | 13560642215116 |
oct | 2135650474407 |
9 | 470230570641 |
10 | 150032513287 |
11 | 586a0495938 |
12 | 250b1703147 |
13 | 111c02243a7 |
14 | 7393c15c7d |
15 | 3d818a3027 |
hex | 22eea27907 |
150032513287 has 2 divisors, whose sum is σ = 150032513288. Its totient is φ = 150032513286.
The previous prime is 150032513263. The next prime is 150032513297. The reversal of 150032513287 is 782315230051.
150032513287 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-150032513287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150032513207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75016256643 + 75016256644.
It is an arithmetic number, because the mean of its divisors is an integer number (75016256644).
Almost surely, 2150032513287 is an apocalyptic number.
150032513287 is a deficient number, since it is larger than the sum of its proper divisors (1).
150032513287 is an equidigital number, since it uses as much as digits as its factorization.
150032513287 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50400, while the sum is 37.
The spelling of 150032513287 in words is "one hundred fifty billion, thirty-two million, five hundred thirteen thousand, two hundred eighty-seven".
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