Base | Representation |
---|---|
bin | 1000101110111101100… |
… | …1110111101010101101 |
3 | 112100021220221022022002 |
4 | 2023233121313222231 |
5 | 4424243112034201 |
6 | 152532510102045 |
7 | 13561160030423 |
oct | 2135731675255 |
9 | 470256838262 |
10 | 150045424301 |
11 | 586a78040a3 |
12 | 250b5aaa925 |
13 | 111c2ac4c46 |
14 | 7395817113 |
15 | 3d82aa376b |
hex | 22ef677aad |
150045424301 has 2 divisors, whose sum is σ = 150045424302. Its totient is φ = 150045424300.
The previous prime is 150045424297. The next prime is 150045424303. The reversal of 150045424301 is 103424540051.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 119647501801 + 30397922500 = 345901^2 + 174350^2 .
It is a cyclic number.
It is not a de Polignac number, because 150045424301 - 22 = 150045424297 is a prime.
Together with 150045424303, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150045424303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75022712150 + 75022712151.
It is an arithmetic number, because the mean of its divisors is an integer number (75022712151).
Almost surely, 2150045424301 is an apocalyptic number.
It is an amenable number.
150045424301 is a deficient number, since it is larger than the sum of its proper divisors (1).
150045424301 is an equidigital number, since it uses as much as digits as its factorization.
150045424301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 29.
Adding to 150045424301 its reverse (103424540051), we get a palindrome (253469964352).
The spelling of 150045424301 in words is "one hundred fifty billion, forty-five million, four hundred twenty-four thousand, three hundred one".
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