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1500514117 is a prime number
BaseRepresentation
bin101100101110000…
…0000011101000101
310212120111000101221
41121130000131011
511033112422432
6404521120341
752120105504
oct13134003505
93776430357
101500514117
11700001513
1235a6290b1
131abb4229b
141033d883b
158baebb97
hex59700745

1500514117 has 2 divisors, whose sum is σ = 1500514118. Its totient is φ = 1500514116.

The previous prime is 1500514097. The next prime is 1500514123. The reversal of 1500514117 is 7114150051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 773618596 + 726895521 = 27814^2 + 26961^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1500514117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1500514091 and 1500514100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1500514157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 750257058 + 750257059.

It is an arithmetic number, because the mean of its divisors is an integer number (750257059).

Almost surely, 21500514117 is an apocalyptic number.

It is an amenable number.

1500514117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1500514117 is an equidigital number, since it uses as much as digits as its factorization.

1500514117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 700, while the sum is 25.

The square root of 1500514117 is about 38736.4701153835. The cubic root of 1500514117 is about 1144.8450091818.

Adding to 1500514117 its reverse (7114150051), we get a palindrome (8614664168).

The spelling of 1500514117 in words is "one billion, five hundred million, five hundred fourteen thousand, one hundred seventeen".