Base | Representation |
---|---|
bin | 1000101110111111100… |
… | …0000110101010000011 |
3 | 112100022110211222100012 |
4 | 2023233320012222003 |
5 | 4424302124200034 |
6 | 152533352015135 |
7 | 13561314300446 |
oct | 2135770065203 |
9 | 470273758305 |
10 | 150053350019 |
11 | 58701227881 |
12 | 250b86914ab |
13 | 111c463b611 |
14 | 73968bb65d |
15 | 3d8361bcce |
hex | 22efe06a83 |
150053350019 has 2 divisors, whose sum is σ = 150053350020. Its totient is φ = 150053350018.
The previous prime is 150053350009. The next prime is 150053350037. The reversal of 150053350019 is 910053350051.
It is a happy number.
150053350019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 150053350019 - 216 = 150053284483 is a prime.
It is a super-2 number, since 2×1500533500192 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (150053350009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75026675009 + 75026675010.
It is an arithmetic number, because the mean of its divisors is an integer number (75026675010).
Almost surely, 2150053350019 is an apocalyptic number.
150053350019 is a deficient number, since it is larger than the sum of its proper divisors (1).
150053350019 is an equidigital number, since it uses as much as digits as its factorization.
150053350019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10125, while the sum is 32.
Adding to 150053350019 its sum of digits (32), we get a palindrome (150053350051).
The spelling of 150053350019 in words is "one hundred fifty billion, fifty-three million, three hundred fifty thousand, nineteen".
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