Base | Representation |
---|---|
bin | 1101101001011011101000… |
… | …1010010110010111001101 |
3 | 1222010111200012021021100220 |
4 | 3122112322022112113031 |
5 | 3431322122133241031 |
6 | 51525223354141553 |
7 | 3106051614601542 |
oct | 332267212262715 |
9 | 58114605237326 |
10 | 15005444040141 |
11 | 4865855a73505 |
12 | 18241a4a218b9 |
13 | 84b01306c3c9 |
14 | 39c3a5922bc9 |
15 | 1b04d557d596 |
hex | da5ba2965cd |
15005444040141 has 48 divisors (see below), whose sum is σ = 21617191411200. Its totient is φ = 9252254017440.
The previous prime is 15005444040101. The next prime is 15005444040149. The reversal of 15005444040141 is 14104044450051.
It is a happy number.
It is not a de Polignac number, because 15005444040141 - 211 = 15005444038093 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15005444040149) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 97671576 + ... + 97825086.
It is an arithmetic number, because the mean of its divisors is an integer number (450358154400).
Almost surely, 215005444040141 is an apocalyptic number.
It is an amenable number.
15005444040141 is a deficient number, since it is larger than the sum of its proper divisors (6611747371059).
15005444040141 is a wasteful number, since it uses less digits than its factorization.
15005444040141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 155694 (or 155675 counting only the distinct ones).
The product of its (nonzero) digits is 25600, while the sum is 33.
Adding to 15005444040141 its reverse (14104044450051), we get a palindrome (29109488490192).
The spelling of 15005444040141 in words is "fifteen trillion, five billion, four hundred forty-four million, forty thousand, one hundred forty-one".
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