Base | Representation |
---|---|
bin | 1000101110111111111… |
… | …1111111111111111111 |
3 | 112100022121202010200120 |
4 | 2023233333333333333 |
5 | 4424303141414103 |
6 | 152533504230023 |
7 | 13561341011214 |
oct | 2135777777777 |
9 | 470277663616 |
10 | 150055419903 |
11 | 58702410a24 |
12 | 250b930b313 |
13 | 111c4bb47bc |
14 | 7396c99b0b |
15 | 3d838ca253 |
hex | 22efffffff |
150055419903 has 8 divisors (see below), whose sum is σ = 200075871408. Its totient is φ = 100035957504.
The previous prime is 150055419887. The next prime is 150055420003. The reversal of 150055419903 is 309914550051.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 150055419903 - 24 = 150055419887 is a prime.
It is a plaindrome in base 16.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (150055499903) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 249001 + ... + 601757.
It is an arithmetic number, because the mean of its divisors is an integer number (25009483926).
Almost surely, 2150055419903 is an apocalyptic number.
150055419903 is a deficient number, since it is larger than the sum of its proper divisors (50020451505).
150055419903 is a wasteful number, since it uses less digits than its factorization.
150055419903 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 494553.
The product of its (nonzero) digits is 121500, while the sum is 42.
Adding to 150055419903 its reverse (309914550051), we get a palindrome (459969969954).
The spelling of 150055419903 in words is "one hundred fifty billion, fifty-five million, four hundred nineteen thousand, nine hundred three".
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